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06-06-2016
Mathematics

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Evaluate Integral: 2sin(2x) from 0, pi/2

Respuesta :

06-06-2016

integral of 2sin(2x) is -cos(2x)
from 0 to pi/2 (sub pi/2 minus sub 0 for x) and then solve
= -cos(2*pi/2)-(-cos0)
= -cos pi + cos 0
= 1 + 1
= 2

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