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MnO2+ 4HCL--->MnCl2+Cl2+2H2O:
if 0.86 mole of MnO2 and 48.2g of HCL react, which reagent will be used up first? How many grams of Cl2 will be produced?
The answers are HCL, and 23.4g.
Show the formula of these answers.

Respuesta :

taskmasters
Which reagent will be used up first? Thee answer is HCl.
We need to convert the amounts of the reactants into moles to see the limiting reactant.

48.2 g HCl ( 1 mol / 36.46 g) = 1.32 mol HCl

Since the ration is 1:4 then the limiting reactant is HCl. To react all of the MnO2 we need 3.44 mol HCl.

How many grams of Cl2 will be produced? 
We use the amount of limiting reactant since it will be used up first.

1.32 mol HCl (1 mol Cl2 / 4 mol HCl) ( 70.9 g Cl2 / 1 mol Cl2) =23.4 g CL2

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