We can start off by using process of elimination. There are only 2 graphs (the first one and last on as appeared on my screen) that can be correct since the others do not have a y-intercept of 3. Then, we can go to the next step which is determining the slope of the remaining lines. The first graph has a slope of -2/5 while the last one has a slope of 5/2. As a result, the first graph, or the graph that has the line with smallest slope showing in quadrant 1 and 2, is the graph of the line y=-2/5x+3.
