Respuesta :
To graph this we find the x- and y-intercepts. The x-intercept would be at 8 and the y-intercept would be at 6.
Explanation:
The equation is 6x+8y=48. An x-intercept is the point where the data crosses the x-axis. All points on this line will have a y-coordinate of 0, so we replace y with 0 and solve:
6x+8(0)=48
6x=48.
Divide both sides by 6:
6x/6=48/6
x=8.
We go to 8 on the x-axis and plot the point.
A y-intercept is the point where the data crosses the y-axis. All points on this line will have an x-coordinate of 9, so we replace x with 0 and solve: 6(0)+8y=48
0+8y=48
8y=48.
Divide both sides by 8:
8y/8 = 48/8
y=6.
We go up to 6 on the y-axis and plot the point. We then draw a line through these two points.
Explanation:
The equation is 6x+8y=48. An x-intercept is the point where the data crosses the x-axis. All points on this line will have a y-coordinate of 0, so we replace y with 0 and solve:
6x+8(0)=48
6x=48.
Divide both sides by 6:
6x/6=48/6
x=8.
We go to 8 on the x-axis and plot the point.
A y-intercept is the point where the data crosses the y-axis. All points on this line will have an x-coordinate of 9, so we replace x with 0 and solve: 6(0)+8y=48
0+8y=48
8y=48.
Divide both sides by 8:
8y/8 = 48/8
y=6.
We go up to 6 on the y-axis and plot the point. We then draw a line through these two points.

Answer:
Refer the figure.
Step-by-step explanation:
Let x be the number of times Emma mows the lawn
and y be the number of hours Emma babysits
Emma earns $6 each time she mows the lawn and $8 per hour for babysitting i.e. [tex]6x+8y[/tex]
She is saving up to buy a new pair of jeans that cost $48.
i.e. [tex]6x+8y\geq 48[/tex]
The y-intercept of the line is the point when x=0,
[tex]6(0)+8y=48[/tex]
[tex]y=\frac{48}{8}[/tex]
[tex]y=6[/tex]
y-intercept is at (0,6)
The x-intercept of the line is the point when y=0,
[tex]6x+8(0)=48[/tex]
[tex]x=\frac{48}{6}[/tex]
[tex]y=8[/tex]
x-intercept is at (8,0).
The shaded area is determined by putting x and y zero.
[tex]6(0)+8(0)\geq 48[/tex]
[tex]0\geq 48[/tex]
False so the region is away from origin.
The solution is the shade area above the solid line.
Refer the attached figure.
