Respuesta :
0.0055*0.03+0.9945*0.01
because 0.55% people are infected and inaccuracy of the test is 3%
and rest 99.45% people are not infected and the inaccuracy of the test is 1%
0.03 and 0.01 are the probability of an error being made in infected and uninfected respectively.
0.01011 is the probability that a randomly chosen person gets an incorrect result.
because 0.55% people are infected and inaccuracy of the test is 3%
and rest 99.45% people are not infected and the inaccuracy of the test is 1%
0.03 and 0.01 are the probability of an error being made in infected and uninfected respectively.
0.01011 is the probability that a randomly chosen person gets an incorrect result.
Answer:
The required probability is 0.01011
Step-by-step explanation:
The test to detect the presence of hepatitis B is 97% accurate
Probability of presence and true = 0.97
Probability of presence and false = 0.03
The test to detect the absence of hepatitis B is 99% accurate
Probability of absence and true = 0.99
Probability of absence and false = 0.01
Probability of infected = 0.55% = 0.0055
Probability of not infected = 1 - 0.0055 = 0.9945
Probability to have an incorrect result : P(infected) and P(presence and false) + P(not infected) and P(absence and false)
= 0.0055 × 0.03 + 0.9945 × 0.01
= 0.01011
Hence, The required probability is 0.01011
