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Hagrid
To solve this quadratic equation, take the square root of both sides.
Since the left side is a perfect square, it will just be reduced to:
4y - 3
For the constant on the right side, the positive and negative roots must be considered.
√72 = ±6√2

Equating the two:
4y - 3 = ±6√2
4y = 3 ± 6√2
y = (3 ± 6√2)/4

y = (3 + 6√2) / 4 = 2.87
and
y = (3 - 6√2) / 4 = -1.37
abidemiokin

The solution of the quadratic equation (4y – 3)² = 72 are y = (6√2 + 3)/4 and y = (-6√2 + 3)/4

Solution to quadratic equations

Quadratic equations are equation that has a degree of 2. Given the quadratic equation as shown:
(4y – 3)² = 72

Take the square root of both sides

√(4y – 3)² = ±√72
4y -3 = ±√72
4y - 3 = ±6√2

4y = ±6√2 + 3

y = (6√2 + 3)/4 and y = (-6√2 + 3)/4

Hence the solution of the quadratic equation (4y – 3)² = 72 are y = (6√2 + 3)/4 and y = (-6√2 + 3)/4

Learn more on quadratic equation here: https://brainly.com/question/17987697

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