Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18. The system that represents Mira’s numbers is below.

x – y = 4

x + y = 18

Which two numbers did Mira pick?

(10, 8)

(18, 4)
(20, 16)
(40, 32)

Respuesta :

W0lf93
Based on the description, the system can be explained in equation form as x - y =4, an (x + y)/2 = 18. Based on these equations, we can plus in numbers from the given answers and come up with a solution where both equations are satisfied. The two numbers that satisfy both equations are (20, 16).

Let

x------> the first number

y-----> the second number

Assume [tex]x> y[/tex]

we know that

[tex]x-y=4[/tex] ----> equation A

[tex]\frac{x}{2}+ \frac{y}{2}=18[/tex]

Multiply by [tex]2[/tex] both sides

[tex]x+y=36[/tex]-----> equation B

Adds equation A and equation B

[tex]x-y=4 \\x+y=36\\------- \\ x+x=4+36\\ 2x=40\\ x=20[/tex]

Find the value of y

[tex]20-y=4[/tex]

[tex]y=20-4=16[/tex]

therefore

the answer is the option

[tex](20,16)[/tex]