Respuesta :

Panoyin
x3 - 2x2 - x[tex]\frac{x^{3} - 3x^{2} + 3x - 2}{x^{2} - x + 1} = \frac{x^{3} - 2x^{2} - x^{2} + 2x + x - 2}{x^{2} - x + 1} = \frac{x^{2}(x) - x^{2}(2) - x(x) + x(2) + 1(x) - 1(2)}{x^{2} - x + 1} = \frac{x^{2}(x - 2) - x(x - 2) - 1(x - 2)}{x^{2} - x + 1} = \frac{(x^{2} - x + 1)(x - 2)}{x^{2} - x + 1} = x - 2[/tex]

The answer is A.

Answer:

A x-2

Step-by-step explanation:

Equation: (x3 – 3x2 + 3x – 2) ÷ (x2 – x + 1)

Work:

(x3 – 3x2 + 3x – 2) ÷ (x2 – x + 1)

(x^2 - x + 1)(x - 2) over x^2 - x + 1

x - 2

Final Answer:

x - 2

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