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In a certain population of rabbits, the allele for brown fur is dominant over the allele for white fur. If 20 out of 100 rabbits have white fur, what is the allele frequency for the recessive allele? The Hardy-Weinberg equation is: [homozygous dominant]2 + 2[heterozygous] + [homozygous recessive]2 = 1

Respuesta :

The Hardy-Weinberg equation is

p2 + 2pq + q2 = 1 and p + q = 1

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

p2 = percentage of homozygous dominant individuals

q2 = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

Here in this question, 20 out of 100 rabbits have white fur which means that the % of homozygous recessive individuals is  

= 20/100 = 0.2

q2 = percentage of homozygous recessive individuals = 0.2

q = square root of 0.2

q = 0.44 = frequency of the recessive allele in the population = 44%

The Hardy-Weinberg equation has been used to determine the frequency of the genotype in the population. The frequency of the recessive allele in the population is 44%.

What is a recessive allele?

A recessive allele is a trait that gets masked in the presence of a dominant trait and is expressed only when in a purebred condition. The frequency is calculated as:

The Hardy-Weinberg equation is:

p² + 2pq + q² = 1,

and p + q = 1

As it is known,

  • Frequency of the dominant allele = p
  • Frequency of the recessive allele = q
  • Percentage of purebred dominant = p²
  • Percentage of purebred recessive = q²
  • Percentage of heterozygous = 2pq

White is recessive = 20% = 0.2

q² = 0.2

q = 0.447

Therefore, the frequency of the recessive allele in the population is 44 %.

Learn more about the Hardy-Weinberg equation here:

https://brainly.com/question/4111398

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