Answer : The correct option is, (a) 1.05 liters
Solution :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 255 kpa
[tex]P_2[/tex] = final pressure of gas = 805 kpa
[tex]V_1[/tex] = initial volume of gas = 2 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]45^oC=273+45=318K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]255^oC=273+255=528K[/tex]
Now put all the given values in the above equation, we get the final volume of gas.
[tex]\frac{255kpa\times 2L}{318K}=\frac{805kpa\times V_2}{528K}[/tex]
[tex]V_2=1.05L[/tex]
Therefore, the final or new volume of gas will be, 1.05 liters
