contestada

Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d = square root of 3h/2, h>0 with d being the distance they can see in miles and h being their eye-level height in feet.

Respuesta :

metchelle
Using the formula given: d = √(3h/2)

We simply substitute the given values of h into the equation and compare the results.

For Wyatt where h = 120:
d = √(3(120)/2)
d = 13.42 miles

For Shawn where h = 270:
d = √(3(270)/2)
d = 20.12 miles

Since the question asks for how much farther can Shawn see, we subtract the results:

20.12 - 13.42 = 6.7

Therefore, Shawn can see 6.7 miles farther.
calculista

Let

d-------> is the distance they can see in miles

h-------> is the eye-level height in feet

we know that

The formula to find the distance d is equal to

[tex] d=\sqrt{\frac{3h}{2}} [/tex]

Step [tex] 1 [/tex]

Find the distance d for Wyatt’s eye-level

[tex] h=120 ft [/tex]

[tex] d=\sqrt{\frac{3*120}{2}} [/tex]

[tex] d=\sqrt{180} [/tex]

[tex] d=13.42 [/tex] [tex] miles [/tex]

Step [tex] 2 [/tex]

Find the distance d for Shawn’s eye-level

[tex] h=270 ft [/tex]

[tex] d=\sqrt{\frac{3*270}{2}} [/tex]

[tex] d=\sqrt{405} [/tex]

[tex] d=20.12 [/tex] [tex] miles [/tex]

Step [tex] 3 [/tex]

Subtract the distance d for Shawn’s eye-level from the distance d for Wyatt’s eye-level

[tex] =20.12-13.42\\ [/tex]

[tex] =6.70 [/tex] [tex] miles [/tex]

therefore

the answer is

Shawn can see [tex] 6.7 [/tex] [tex] miles [/tex] farther