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What is the product of d – 9 and 2d2 + 11d – 4?

A=2d3 – 7d2 – 103d + 36
B=2d3 – 7d2 – 95d + 36
C=2d3 + 7d2 – 95d + 36
D=2d3 + 7d2 – 103d + 36

Respuesta :

SociometricStar

Answer:

[tex]2d^3-7d^2-103d+36[/tex]

A is the correct option.

Step-by-step explanation:

We have to find the product

[tex](d-9)(2d^2+11d-4)[/tex]

Using the distributive property (term by term multiplication), we have

[tex]d\cdot2d^2+d\cdot11d+d\cdot(-4)-9\cdot2d^2-9\cdot11d-9\cdot(-4)[/tex]

On multiplying, we get

[tex]2d^3+11d^2-4d-18d^2-99d+36[/tex]

Combine like terms

[tex]2d^3-7d^2-103d+36[/tex]

A is the correct option.

boffeemadrid

Answer:

(A)[tex]2d^3-7d^2-103d+36[/tex]

Step-by-step explanation:

It is given that there are two functions that are [tex](d-9)[/tex] and [tex]2d^2+11d-4[/tex] and

We have to find the product of [tex](d-9)[/tex] and [tex]2d^2+11d-4[/tex], therefore we can write as:

[tex](d-9)(2d^2+11d-4)[/tex]

[tex]2d^3-18d^2+11d^2-99d-4d+36[/tex]

[tex]2d^3-7d^2-103d+36[/tex]

which is the required product.

Thus, Option A is correct.

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