Respuesta :

1Jr
Second statement 2x2 + 8x – 24 = 0 Is true for the given conditions. When x = -6 2x2 + 8x – 24 = 0 Becomes 2(-6)2 + 8(-6) – 24 = 0 2(36) - 48 - 24 = 0 72 - 48 - 24 = 0 0 = 0 Which is true. When x = 2 2x2 + 8x – 24 = 0 Becomes 2(2)2 + 8(2) – 24 = 0 2(4) + 16 - 24 = 0 8 + 16 - 24 = 0 0 = 0 Which is true. So 2x2 + 8x – 24 = 0 will be answer.
calculista

we know that

using a graph tool

let's proceed to graph each case to determine the roots

case 1) [tex] 2x^{2} - 16x + 12 = 0 [/tex]

the roots are

[tex] x1=0.8\ x2=7.2 [/tex] ------> is not the solution

see the attached figure N [tex] 1 [/tex]

case 2) [tex] 2x^{2} +8x -24 = 0 [/tex]

the roots are

[tex] x1=-6\ x2=2 [/tex]

see the attached figure N [tex] 2 [/tex] --------> is the solution

case 3) [tex] 3x^{2} - 4x - 12 = 0 [/tex]

the roots are

[tex] x1=-1.4\ x2=2.8 [/tex]------> is not the solution

see the attached figure N [tex] 3 [/tex]

case 4) [tex] 3x^{2} +12x +36 = 0 [/tex]

the graph does not have x-intercepts

see the attached figure N [tex] 4 [/tex] ------> is not the solution

therefore

the answer is

the solution is

[tex] 2x^{2} +8x -24 = 0 [/tex]

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