There are five different colored cards in a hat (red, blue, green, yellow, and black). A card is randomly drawn and not replaced. Then a second card is drawn. What is the probability that the first card will be red and the second card will be blue?

4%
5%
20%
25%

First, for any of the five cards being drawn, there is a 1/5 chance, or 20%. So, the probability of a red card being drawn is 1/5. Then, since the card is not replaced, it becomes a 1/4, or 25%, chance of any card being drawn (besides red). So, the probability of a blue card being drawn is 1/4. So in order to find what the question is asking, we'll need to multiply the two fractions together.

1/5 x 1/4 = 1/20

1/20 = 5%

Therefore, the correct answer is 5%, or the second option.

Hope this helps!! :)

warriorwarrior warriorwarrior · Answer 2 · 2021-08-17T01:57:19+02:00

warriorwarrior warriorwarrior

17-08-2021

Answer:

5%

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There are five different colored cards in a hat (red, blue, green, yellow, and black). A card is randomly drawn and not replaced. Then a second card is drawn. What is the probability that the first card will be red and the second card will be blue? 4% 5% 20% 25%

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There are five different colored cards in a hat (red, blue, green, yellow, and black). A card is randomly drawn and not replaced. Then a second card is drawn. What is the probability that the first card will be red and the second card will be blue?

4%
5%
20%
25%