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If you would like to find AB - C in simplest form, you can do this using the following steps:

A = n
B = 2n + 6
C = n^2 - 1

AB - C = n * (2n + 6) - (n^2 - 1) = 2n^2 + 6n - n^2 + 1 = n^2 + 6n + 1

The correct result would be B=n2 + 6n + 1.

Answer:

[tex]AB-C=n^{2} +6n +1[/tex]

Step-by-step explanation:

Given :

[tex]A = n[/tex]

[tex]B=2n+6[/tex]

[tex]C=n^{2} -1[/tex]

To Find: AB-C

Solution:

Since A=n

B=2n+6

So, [tex]AB=2n^{2} +6n[/tex]

Now since [tex]C=n^{2} -1[/tex]

Thus [tex]AB-C=2n^{2} +6n-(n^{2} -1)[/tex]

⇒[tex]AB-C=2n^{2} +6n-n^{2} +1[/tex]

⇒ [tex]AB-C=n^{2} +6n +1[/tex]

Thus option B is correct .

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