A wire that is 0.36 meters long moves perpendicularly through a magnetic field at a speed of 0.21 meters/second. The induced emf produced in the wire is 0.45 volts. What is the magnetic field strength?

Respuesta :

0.034 newtons/amp·meter

Answer:

Magnetic field strength, B = 5.95 Tesla

Explanation:

It is given that,

Length of wire, l = 0.36 m

It is moving perpendicularly through a magnetic field at a speed of, v = 0.21 m/s

Induced emf, E = 0.45 volts

The mathematical expression for induced emf is given by :

[tex]E=\dfrac{d\phi}{dt}=Blv[/tex]

[tex]\dfrac{d\phi}{dt}[/tex] is the rate of change of magnetic flux,

B is magnetic field

So, [tex]B=\dfrac{E}{lv}[/tex]

[tex]B=\dfrac{0.45}{0.36\times 0.21}[/tex]

B = 5.95 Tesla

Hence, this is the required solution.