Respuesta :
The following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction.
2HNO3 + S ---> 2NO + H2SO4
2HNO3 + S ---> 2NO + H2SO4
Explanation:
An equation that contains equal number of atoms on both reactant and product side is known as a balanced chemical equation.
Whereas when there will be increase in oxidation number of the atom then it is known as oxidation. When there is decrease in oxidation number of the atom then it is known as reduction.
For example, [tex]4HNO_{3} + S \rightarrow NO + H_{2}SO_{4} + H_{2}O[/tex]
Oxidation half reaction : [tex]S \rightarrow H_{2}SO_{4} + 6e^{-}[/tex]
Reduction half reaction : [tex]HNO_{3} + 3e^{-} \rightarrow NO[/tex]
Therefore, we can conclude that sulfur atom has undergone oxidation and nitrogen atom has undergone reduction.