A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 12 inches. If the lizard is 8 inches from a point of tangency, find the direct distance between the lizard and the cactus (x). If necessary, round to the hundredths place.

Respuesta :

the answer should be 6 if i am right

Answer:

10 in

Step-by-step explanation:

We are given that

Diameter of cactus=d=12 in

Radius of cactus=[tex]\frac{d}{2}=\frac{12}{2}=6 in[/tex]

Distance of lizard from point of tangency=8 in

We have to find the direct distance between lizard and cactus.

In triangle OAB,

OA=6 in

AB=8 in

Pythagorous theorem: [tex](Hypotenuse)^2=(base)^2+(perpendicular\;side)^2[/tex]

Using pythagorous theorem

[tex]OB^2=(6)^2+(8)^2=100[/tex]

[tex]OB=\sqrt{100}=10 in[/tex]

Hence, the direct distance of lizard from cactus=10 in

Ver imagen lublana