anonymous1234567
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A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?

Respuesta :

Kalahira
Use Charles's Law., which relates volume and temperature for gases at constant pressure. => V1/T1 = V2/T2. This formula requires the use of absolute temperatures=> T1 = 25.0 + 273.15K = 298.15K, and T2 = 40.0 + 273.15K = 313.15K. Therefore: 3.50 L / 298.15K = x / 313.15K => x = 3.50L * 313.15K / 298.15K = 3.68 L. Answer: 3.68 L
irocktheworld11

yes, according to charles law, this would be equal to 3.68 L

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