Given:
rate = k [A]2
concentration is 0.10 moles/liter
rate is 2.7 × 10-5 M*s-1
Required:
Value of k
Solution:
rate = k [A]2
2.7 × 10-5 M*s-1 = k (0.10 moles/liter)^2
k = 2.7 x 10^-3 liter per mole per second
Answer:The value of rate constant is [tex]2.7\times 10^{-3} Ls^{-1} mol^{-1}[/tex].
Explanation:
Concentration of [A]=0.10 mol/L
The rate of the reaction = [tex]2.7\times 10^{-5} M/s[/tex]
Rate constant = k
The given rate law:
[tex]R=k[A]^2[/tex]
[tex]2.7\times 10^{-5} M/s=k\times (0.10 mol/L)^2[/tex]
[tex]k=\frac{2.7\times 10^{-5} mol/L s}{0.10 mol/L\times 0.10 mol/L}=2.7\times 10^{-3} Ls^{-1} mol^{-1}[/tex]
The value of rate constant is [tex]2.7\times 10^{-3} Ls^{-1} mol^{-1}[/tex].
