Respuesta :
From the kinematic equations, s(t) = s_in + (v_in)(t) – (1/2)(g)(t^2). This means that there is an initial distance of 4, initial velocity of 32 and acceleration (in opposite direction of the motion) of 32. Option 4 shows the correct answer.
By definition, the equation of movement in its generic form is given by:
[tex] h(t) = -\frac{1}{2}gt^2 + v0t + h0 [/tex]
Where,
g: acceleration due to gravity
v0: initial speed
h0: initial height
The equation for the arrow is given by:
[tex] h = 4 + 32t-16t ^ 2 [/tex]
Then, according to the definition, the initial velocity of the arrow is:
[tex] v0 = 32 [/tex]
Answer:
4 The arrow is fired with an initial upward velocity of 32 ft / s.