HH,HT,TT,TH
As evident from above sample space,the probability of finding exactly one Head
2\4 I.E 1\2
so the answer is B
Option B. [tex]\frac{1}{2}[/tex] is correct.
Possible chances of occurring an event are known as the probability of that event.
Sample space for tossing two coins is :
( {H,H} , {H,T} , {T,T} , {T,H} )
Probability of an event = [tex]\frac{favourable}{Total}[/tex]
Exactly one head appeared 2 times i.e., {H,T} or {T,H}
Thus, Favourable outcomes = 2
Total outcomes = 4
P (Exactly one head) = [tex]\frac{2}{4} = \frac{1}{2}[/tex]
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