BunniBu2
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There are 200 students in the 7th grade class at Manchester Middle School. Of these students, 22% play football and 12% play baseball. Eight students play on both teams. What is the probability that a student plays either football or baseball?

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mehnameiskat
(Are you also doing the apex geometry final? I have a question just like this on mine)

I remember answering 30%. Im sorry if this doesnt help much, but it has a chance or being correct?

Answer: There is 30% student plays either football or baseball.

Step-by-step explanation:

Since we have given that

Total number of students = 200

Percentage of students who play football = 22%

Number of students who play football n(F) is given by

[tex]0.22\times 200\\\\=44[/tex]

Percentage of students who play baseball = 12%

Number of students who play baseball n(B) is given by

[tex]0.12\times 200\\\\=24[/tex]

Number of students who play on both teams n(F∩B) = 8

According to rules, it becomes,

[tex]n(F\cap B)=n(F)+n(B)-n(F\cap B)\\\\n(F\cap B)=44+24-8=60[/tex]

Probability that a student plays either football or baseball is given by

[tex]\dfrac{60}{200}\\\\=0.3\\\\=30\%[/tex]

Hence, there is 30% student plays either football or baseball.

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