Respuesta :

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[tex]_{3}P_{0} = \frac{3!}{(3 - 0)!}[/tex]
[tex]_{3}P_{0} = \frac{3!}{3!}[/tex]
[tex]_{3}P_{0} = \frac{3 * 2 * 1}{3 * 2 * 1}[/tex]
[tex]_{3}P_{0} = 1[/tex]

The answer is B.

Answer:

Option B. 1

Step-by-step explanation:

We have to find the value of P(3, 0)

We have to find the value of given permutation [tex]^{3}P_{0}[/tex]

Since we know [tex]^{a}P_{b}=\frac{a!}{(a-b)!}[/tex]

Here a = 3

b = 0

[tex]^{3}P_{0}=\frac{3!}{(3-0)!}[/tex]

[tex]=\frac{3!}{3!}=1[/tex]

Therefore, option B. 1 is the answer.

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