Answer:
Option B , C and E are correct
[tex]y^2-5y =750[/tex]
[tex]750 -y(y-5)=0[/tex]
(y+25)(y-30)=0
Step-by-step explanation:
Given : Area of rectangular room is 750 square feet.
Width of the room is 5 feet less than the length of the room.
Let y be the length of the room
then,
As per the given condition
width of the room is: y-5
Area of rectangle is multiply the length by its width.
Area of rectangle = [tex]length \times width[/tex]
Substitute the given values in above formula we get;
[tex]750 = y(y-5)[/tex] ......[1]
or we can write this as;
750 -y(y-5)=0
[1] ⇒[tex]y(y-5) =750[/tex] or
[tex]y^2-5y =750[/tex] or
[tex]y^2-5y-750=0[/tex]
[tex]y^2-25y+30y-750=0[/tex]
(y+25)(y-30)=0
Therefore, the equation which can be used to solve for y are;
[tex]y^2-5y =750[/tex] , [tex]750 -y(y-5)=0[/tex] and (y+25)(y-30)=0
