Answer : The molar volume of the gas will be, 44.82 L
Solution :
Using ideal gas equation,
[tex]PV=nRT[/tex]
where,
n = number of moles of gas = 1 mole
P = pressure of the gas = 0.5 atm
T = temperature of the gas = 273 K
R = gas constant = 0.0821 Latm/moleK
V = volume of the gas.
Now put all the given values in the above equation, we get the molar volume of the gas.
[tex](0.5atm)\times V=(1mole)\times (0.0821Latm/moleK)\times (273K)[/tex]
[tex]V=44.82L[/tex]
Therefore, the molar volume of the gas will be, 44.82 L