The mass of a stroller and the child it carries is 23.7 kg. A man pushes the stroller with a force of 142 N at an angle of 38.0° to the vertical. The stroller experiences a friction force of 24.0 N due to the brake accidentally being on. What is the stroller's acceleration forward?
A. 5.99 m/s2
B. 3.90 m/s2
C. 2.68 m/s2
D. 4.98 m/s2

Respuesta :

the horizontal resultant force applied is 142*Cos(38) which is 135.62N

24N of opposing force
therefore the total force acting on the stroller is 135.62-24=
111.62N

applying the formula f=ma
where f is force
m= mass
a= acceleration
plugging the values we get 
the stroller's acceleration forward as 3.90 m/s^2