Respuesta :

saturn98
Let us assume then that the center is the origin.  If the major axis is 18, then a = 9 and a^2=81.  If the minor axis is 16, then b = 8 and b^2=64.  Now you can write the equation.  Remember that this ellipse is vertical and so a^2 goes under y^2

Answer:

x²/64 + y²/81 = 1

Step-by-step explanation:

Standard form of an equation for the ellipse is [tex]\frac{x^{2} }{a^{2}}+\frac{y^{2} }{b^{2} }=1[/tex]

Here b is the length of vertical major axis = 9

and minor axis of length a = 8

Therefore the equation of the ellipse will be

[tex]\frac{x^{2} }{8^{2} }+\frac{y^{2} }{9^{2} } =1[/tex]

[tex]\frac{x^{2} }{64}+\frac{y^{2} }{81}=1[/tex]

So the answer is x²/64 + y²/81 = 1

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