Answer:
0.5959 or 59%
Step-by-step explanation:
The number of total elders who have insurance is the sum of the elders who have been hospitalized and have insurance and the elders who have not been hospitalized and have insurance.
Hospitalized, have insurance:
[tex]P(H\cap I)=0.57*0.54=0.3078[/tex]
Not hospitalized, have insurance:
[tex]P(NH\cap I)=(1-0.57)*(1-0.33)=0.2881[/tex]
Therefore, the probability that an elder selected at random has insurance is:
[tex]P(I)=P(H\cap I)+P(NH\cap I)\\P(I)= 0.3078+0.2881\\P(I) = 0.5959\ or\ 59\%[/tex]
