Answer:
v = 0.9875 c
Explanation:
This is an exercise of time dilation in special relativity, which is described by the equation
t = [tex]t_{p}[/tex] γ
γ = 1 / √ (1 — v² / c²)
The most important is to find respect for which system the measurement is performed.
Since the particle is still, the measured time is the proper time [tex]t_{p}[/tex] = 2.7196 10-6 s, in the system where the particles move t = 17,258 10-6 s
Let's clear dam
γ = t / [tex]t_{p}[/tex]
γ = 17,258 10-6 / 2.7196 10-6
γ = 6.345
γ = 1 / √ (1-β²)
1-β² = 1 /γ²
β = √ (1- 1 / γ²)
β = √ (1 - 1 / 6,345²)
β = 0.9875
v / c = 0.9875
v = 0.9875 c
