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Assume that a particle moves in a velocity field defined by V (x, y) = (x + 6)i + (y − 3)j. Find the path of a particle with initial starting point (1, 1).

Respuesta :

Khoso123

Answer:

[tex]V(1,1)=7i-2j[/tex]

Explanation:

V(x,y)=(x+6)i+(y-3)j ............eq1

As intial point are given (1,1)

which means x=1,y=1

put these values in eq1

V(1,1)=(1+6)i+(1-3)j

V(1,1)=7i-2j

And its magnitude given as

|V(1,1)|=[tex]\sqrt{(7)^{2}+(-2)^{2}  }[/tex]

|V(1,1)| =7.28

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