Answer:
Induced emf is 0.0492 volts and it is in clockwise direction.
Explanation:
It is given that,
Initial circumference of a circular loop, C = 165 cm = 1.65 m
Radius, r = 0.825 m
Time, t = 9 s
(A) The circumference is decreasing at a constant rate of 12 cm/s due to a tangential pull on the wire.
[tex]\dfrac{dC}{dt}=-0.12\ m/s[/tex]
[tex]\dfrac{d(2\pi r)}{dt}=-0.12\ m/s[/tex]
[tex]\dfrac{dr}{dt}=0.019\ m/s[/tex]
The induced emf is given by :
[tex]\epsilon=-\dfrac{d(BA)}{dt}[/tex]
[tex]\epsilon=2\pi Br\dfrac{dr}{dt}[/tex]
[tex]\epsilon=2\pi \times 0.5\times 0.825\times 0.019[/tex]
[tex]\epsilon=0.0492\ volts[/tex]
(B) the direction of induced emf is clockwise as viewed looking along the direction of the magnetic field inside the loop.
Hence, this is the required solution.