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A military jet cruising at an altitude of 12.0km and speed of 1300./kmh burns fuel at the rate of 46.2/Lmin. How would you calculate the amount of fuel the jet consumes on a 1150.km mission? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. fuel=consumed1330kmh⋅

Respuesta :

Answer:

2,452.12 L of fuel the jet consumes on a 1150 km mission.

Explanation:

Speed of the jet = 1300 km/h

1 hour = 60 minutes

[tex]1300 km/h=\frac{1300 km}{60 min}=21.667 km/min[/tex]

Rate at which jet consumes fuel = 46.2 L/min

Distance covered by jet by consuming 1 liter fuel or mileage = R

R = [tex]\frac{21.667 km/min}{46.2 L/min}=0.4690 km/L[/tex]

The amount of fuel the jet consumes on a 1150 km mission will = V

Amount of fuel = [tex]\frac{Distance}{Mileage}[/tex]

[tex]V=\frac{1150 km}{0.4690 km/L}=2,452.12 L[/tex]

2,452.12 L of fuel the jet consumes on a 1150 km mission.

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