Respuesta :
Answer:
The molarity of the [tex]Pb(NO_3)_2[/tex] solution = 0.1895 M
Explanation:
The mass of the [tex]PbCl_2[/tex] obtained = 10.55 g
Molar mass of [tex]PbCl_2[/tex] = 278.1 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{10.55\ g}{278.1\ g/mol}[/tex]
[tex]Moles_{PbCl_2}= 0.0379\ mol[/tex]
From the reaction:-
[tex]Pb(NO_3)_2+2NaCl\rightarrow PbCl_2+2NaNO_3[/tex]
1 mole of [tex]PbCl_2[/tex] is produced from 1 mole of [tex]Pb(NO_3)_2[/tex]
Also,
0.0379 mole of [tex]PbCl_2[/tex] is produced from 0.0379 mole of [tex]Pb(NO_3)_2[/tex]
Mole of [tex]Pb(NO_3)_2[/tex] = 0.0379 mol
Volume = 200.0 mL = 0.2 L ( 1 mL = 0.001 L )
Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.
The expression for the molarity, according to its definition is shown below as:
[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]
Thus,
[tex]Molarity=\frac{0.0379}{0.2}\ M = 0.1895\ M[/tex]
The molarity of the [tex]Pb(NO_3)_2[/tex] solution = 0.1895 M
