Answer:
174.402 Torr is the partial pressure of oxygen gas.
Explanation:
According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.
[tex]P_T=p_{1}+p_{2}+p_{3}...p_{n}[/tex]
where,
[tex]P_T[/tex] = Total pressure
[tex]p_{1}[/tex] = partial pressure of gas-1
[tex]p_{2}[/tex] = partial pressure of gas-2
[tex]p_{3}[/tex] = partial pressure of gas-3
[tex]p_{n}[/tex] = partial pressure of nth gas in the mixture
We have:
[tex]P_T= 1 atm = 760 Torr[/tex]
[tex]p_{CO_2}=0.285 Torr[/tex]
[tex]p_{N_2}=585.313 Torr[/tex]
[tex]p_{O_2}=?[/tex]
Now put all the given values is expression, we get the partial pressure of the [tex]O_2[/tex] gas.
[tex]P_T=p_{CO_2}+p_{N_2}+p_{O_2}[/tex]
[tex]760 Torr=0.285 Torr+585.313 Torr+p_{O_2}[/tex]
[tex]p_{O_2}=174.402 Torr [/tex]
174.402 Torr is the partial pressure of oxygen gas.