Respuesta :
Answer:
2.1 atm is the partial pressure of gas C.
Explanation:
to calculate partial pressure of gas C we will use Dalton's law.
According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.
[tex]P_T=p_{1}+p_{2}+p_{3}...p_{n}[/tex]
where,
[tex]P_T[/tex] = Total pressure
[tex]p_{1}[/tex] = partial pressure of gas-1
[tex]p_{2}[/tex] = partial pressure of gas-2
[tex]p_{3}[/tex] = partial pressure of gas-3
[tex]p_{n}[/tex] = partial pressure of nth gas in the mixture
We have:
[tex]P_T= 7.47 atm [/tex]
[tex]p_{A}=1.59 atm[/tex]
[tex]p_{B}=3.78 atm[/tex]
[tex]p_{C}=?[/tex]
Now put all the given values is expression, we get the partial pressure of the [tex]O_2[/tex] gas.
[tex]P_T=p_{A}+p_{B}+p_{C}[/tex]
[tex]7.47 atm=1.59 atm+3.78 atm+p_{C}[/tex]
[tex]p_{C}=2.1 atm [/tex]
2.1 atm is the partial pressure of gas C.
