Answer:
after 1st half life the 10g of isotope will remain 5 g.
Explanation:
Given data:
Mass of isotope = 10 g
Mass remain after one half life = ?
Solution:
At time zero = 10 g
AT 1st half life = 10 g/2 = 5 g
So after 1st half life the 10g of isotope will remain 5 g.