If the equilibrium constant for a two-electron redox reaction at 298 K is 1.0×10−4, calculate the corresponding ΔG∘ and E∘cel under standard conditions.

ΔG∘ =

E∘cell =

Respuesta :

Answer: [tex]\Delta G^0=22823J[/tex]

[tex]E^0=-0.12V[/tex]

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_{eq}[/tex]

The Gibbs free energy is related to equilibrium constant by following relation:

[tex]\Delta G^0=-2.303RTlog K[/tex]

R = gas constant = 8.314 J/Kmol

T = temperature in kelvin =[tex]298K[/tex]

K = equilibrium constant

[tex]\Delta G^0=-2.303RTlog K[/tex]

[tex]\Delta G^0=-2.303\times 8.314\times 298\times log(1.0\times 10^{-4})[/tex]

[tex]\Delta G^0=22823J[/tex]

The standard emf of a cell is related to Gibbs free energy by following relation:

[tex]\Delta G^0=-nFE^0[/tex]

[tex]\Delta G^0[/tex] = gibbs free energy  = 22823J

n= no of electrons gained or lost  = 2

F= faraday's constant  = 96500 C

[tex]E^0[/tex] = standard emf

[tex]22823J=-2\times 96500\times E^0[/tex]

[tex]E^0=-0.12V[/tex]