A tank is filled with an ideal gas at 400 K and pressure of 1.00 atm.
The tank is heated until the pressure of thegas in the tank doubles. What is the temperature of the gas?
200\rm K
400\rm K
600\rm K
800\rm K
Correct

Respuesta :

To find the temperature it is necessary to use the expression and concepts related to the ideal gas law.

Mathematically it can be defined as

[tex]PV=nRT[/tex]

Where

P = Pressure

V = Volume

n = Number of moles

R = Gas constant

T = Temperature

When the number of moles and volume is constant then the expression can be written as

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]

Or in practical terms for this exercise depending on the final temperature:

[tex]T_2 = \frac{P_2T_1}{P_1}[/tex]

Our values are given as

[tex]T_1 = 400K\\P_1 = 1atm\\P_2 = 2atm[/tex]

Replacing

[tex]T_2 = \frac{(2)(400)}{1}\\T_2 = 800K[/tex]

Therefore the final temperature of the gas is 800K