Respuesta :
Answer:
Rate of production of [tex]P_4 :0.0005105 M/s[/tex]
Rate of production of [tex]H_2 :0.003063 M/s[/tex]
Explanation:
Rate of the reaction is defined as the change in concentration of any one of the reactants or product per unit time.
[tex]4 PH_3(g) \rightarrow P_4(g) + 6 H_2(g)[/tex]
Rate of the reaction = R
[tex]R=-\frac{1}{4}\frac{d[PH_3]}{dt}=\frac{1}{1}\frac{d[P_4]}{dt}=\frac{1}{6}\frac{d[H_2]}{dt}[/tex]
Rate at which phosphorus hydride consumed or disappeared= [tex]-\frac{d[PH_3]}{dt}[/tex]
[tex]\frac{[PH_3]}{1 s}[/tex]
[tex]=\frac{0.0049 mol}{2.4 L\times 1 s}=0.002042 M/s[/tex]
[tex]-\frac{d[PH_3]}{dt}=0.002042 M/s[/tex]
[tex]R = -\frac{1}{4}\frac{d[PH_3]}{dt}=\frac{1}{4}\times 0.002042 M/s=0.0005105 M/s[/tex]
Rate of production of [tex]P_4[/tex] :
[tex]R=\frac{1}{1}\frac{d[P_4]}{dt}[/tex]
[tex]\frac{d[P_4]}{dt}=\frac{1}{1}\times 0.0005105 M/s=0.0005105 M/s[/tex]
Rate of production of [tex]H_2[/tex] :
[tex]R=\frac{1}{6}\frac{d[P_4]}{dt}[/tex]
[tex]\frac{d[H_2]}{dt}=\frac{6}{1}\times 0.0005105 M/s=0.003063 M/s[/tex]
The rates of production of [tex]\bold {P_4 }[/tex]and [tex]\bold {H_2 }[/tex] in the given experiment is 0.0005105 M/s and 0.003063 M/s.
What is the rate of reaction?
The rate of reaction is the rate at which the reactant change into product or simply as rate of product formation.
The given reaction is:
[tex]\bold{4 PH_3(g) \rightarrow P_4(g) + 6 H_2(g)}[/tex]
The reaction rate:
[tex]R = \dfrac 14 \dfrac {d[PH_3]}{dt} = \dfrac 11 \dfrac {d[P_4]}{dt} = \dfrac 16 \dfrac {d[P_2]}{dt}[/tex]
Rate of disappearance of [tex]\bold {PH_3}[/tex] =
[tex]-\dfrac {dPH_3}{dt} =\dfrac 14\times \dfrac {0.0049}{2.4 }\times 1{\rm \ s} \\\\-\dfrac {dPH_3}{dt}= 0.002042 {\rm \ M/s}[/tex]
So, the rate of [tex]\bold {P_4 }[/tex] production:
[tex]\dfrac {dP_4 }{dt } =\dfrac 11\times 0.0005105 \\\\\dfrac {dP_4 }{dt } = 0.0005105 {\rm \ M/s}[/tex]
The rate of [tex]\bold {H_2 }[/tex] production:
[tex]\dfrac {dH_2}{dt } =\dfrac 16\times 0.0005105 \\\\\dfrac {dH_2 }{dt } = 0.003063 {\rm \ M/s}[/tex]
Therefore, the rates of production of [tex]\bold {P_4 }[/tex]and [tex]\bold {H_2 }[/tex] in the given experiment is 0.0005105 M/s and 0.003063 M/s.
Learn more about rate of reaction:
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