2. A line passes through (1, -5) and (-3, 7).
a. Write an equation for the line in point-slope form.
b. Rewrite the equation in slope-intercept form.
©
A y - 5 = 3(x + 1); y = 3x + 8
.
D y + 5 = -3(x - 1); y = -3x - 2

The answer would be d) y + 5 = -3(x - 1); y = -3x - 2
The answer is d because you would find the slope by doing y2 - y1 / x2 - x1 ( 7 + 5 / -3 - 1 ) which equals -3. You would use your first coordinate and the slope -3 then plug that into the point slope formula ( y + 5 = -3(x - 1) ). If you simplify that equation you would get y = -3x - 2

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2. A line passes through (1, -5) and (-3, 7). a. Write an equation for the line in point-slope form. b. Rewrite the equation in slope-intercept form. © A y - 5 = 3(x + 1); y = 3x + 8 . D y + 5 = -3(x - 1); y = -3x - 2

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2. A line passes through (1, -5) and (-3, 7).
a. Write an equation for the line in point-slope form.
b. Rewrite the equation in slope-intercept form.
©
A y - 5 = 3(x + 1); y = 3x + 8
.
D y + 5 = -3(x - 1); y = -3x - 2