To solve this problem it is necessary to apply the concepts related to wavelength as a function of speed and frequency. In mathematical terms it can be expressed as
[tex]\lambda = \frac{v}{f}[/tex]
Where,
v = Velocity
f = Frequency
According to our values the frequency (f) is 320Hz and the speed (v) is 339m / s.
Replacing in the given equation we have to,
[tex]\lambda = \frac{v}{f}\\\lambda = \frac{339}{320}\\\lambda = 1.059m\approx 1.06m[/tex]
Therefore the wavelength of this sound wave is 1.06m
