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When a certain ideal gas thermometer is immersed in a water-ice mixture at 273.15 K, the mercury level in the right arm is 102 mm above the reference mark. When this thermometer is then immersed in a liquid of unknown temperature, the mercury level is 25 mm above the reference mark.
Part AWhat is the temperature of the liquid?

Respuesta :

boffeemadrid

Answer:

66.94852 K

Explanation:

[tex]P_1[/tex] = Initial pressure = 102 mmHg

[tex]P_2[/tex] = Final pressure = 25 mmHg

[tex]T_1[/tex] = Initial temperature = 273.15 K

[tex]T_2[/tex] = Final temperature

From ideal gas law we have the relation

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}\\\Rightarrow T_2=\frac{T_1\times P_2}{P_1}\\\Rightarrow T_2=\frac{273.15\times 25}{102}\\\Rightarrow T_2=66.94852\ K[/tex]

The temperature of the liquid is 66.94852 K

jayilych4real

The temperature of the liquid is:

  • 66.94852 K

What is Temperature?

This refers to the degree of hotness or coldness of a particular surface area at any given time.

Therefore, we have the

P1 Initial pressure = 102 mmHg

P2 Final pressure = 25 mmHg

T1 Initial temperature = 273.15 K

T2 Final temperature= ?

From ideal gas law we have the relation

P2/T1= P2/P2

=> T2 = (T1 x P2)/P1

Therefore, T2= 273.15 x 25/102

= 66.94852 K

The temperature of the liquid is 66.94852 K

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https://brainly.com/question/16559442

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