A piece of aluminum (bulk modulus 7.1 x 1010 N/m2) is placed in a vacuum chamber where the air pressure is 0.781 x 105 Pa. The vacuum pump is then turned on and the pressure is further reduced to zero. Determine the fractional change V/V0 in the volume of the aluminum

Respuesta :

Answer:

[tex]{\dfrac{\Delta V}{V}}=11\times 10^{-7}[/tex]

Explanation:

Given that

Bulk modulus ,K = 7.1 x 10¹⁰  Pa

The pressure P₁ = 0.781 x 10⁵ Pa

The final pressure P ₂ = 0 Pa

We know that bulk modulus given as

[tex]K=\dfrac{\Delta P}{\dfrac{\Delta V}{V}}[/tex]

Now by putting the values

[tex]K=\dfrac{\Delta P}{\dfrac{\Delta V}{V}}[/tex]

[tex]7.1\times 10^{10}=\dfrac{0.781\times 10^5}{\dfrac{\Delta V}{V}}[/tex]

[tex]{\dfrac{\Delta V}{V}}=\dfrac{0.781\times 10^5}{7.1\times 10^{10}}[/tex]

[tex]{\dfrac{\Delta V}{V}}=11\times 10^{-7}[/tex]

Therefore fractional change will be 11 x 10⁻⁷.