Answer:
a)L =0.353 kg.m²/s
b)L =0.53 kg.m²/s
Explanation:
Given that
m= 2.95 kg
R = 0.2 m
ω = 5.99 rad/s
a)
Moment of inertia of disk about center
[tex]I=\dfrac{mR^2}{2}\ kg.m^2[/tex]
[tex]I=\dfrac{2.95\times 0.2^2}{2}\ kg.m^2[/tex]
I=0.059 kg.m²
L = I ω
L = 0.059 x 5.99
L =0.353 kg.m²/s
b)
[tex]r=\dfrac{R}{2}\ m[/tex]
r= 0.1 m
[tex]I=\dfrac{mR^2}{2}+mr^2\ kg.m^2[/tex]
[tex]I=\dfrac{2.95\times 0.2^2}{2}+2.95\times 0.1^2\ kg.m^2[/tex]
I=0.0885 kg.m²
L = 0.0885 x 5.99
L =0.53 kg.m²/s
