The velocity of the object after 4.0 seconds is 8.0 m/s
Explanation:
The motion of the object is a uniformly accelerated motion (constant acceleration), therefore we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the object in this problem, we have:
u = 0 (it starts from rest)
[tex]a=2.0m/s^2[/tex] is the acceleration
t = 4.0 s is the time elapsed
Solving for v, we find the final velocity:
[tex]v=0+(2.0)(4.0)=8.0 m/s[/tex]
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