Respuesta :
Question is Incomplete, Complete question is given below.
Brand A scooter has a top speed that goes 2 miles per hour faster than Brand B. If after 3 hours, Brand A scooter traveled 40.2 miles at its top speed, at what rate did Brand B scooter travel at its top speed if traveled the same distance? Write an equation to determine the solution.
Answer:
The equation to determine solution is [tex]40.2 = (2+x)3[/tex].
Brand B will travel at a rate of 11.4 miles per hour.
Step-by-step explanation:
Given:
Distance traveled by brand A = 40.2 miles
time required to cover distance = 3 hours.
Brand A scooter has a top speed that goes 2 miles per hour faster than Brand B
Let brand B scooter has a top speed of x
Hence Brand A scooter has a top speed will be [tex]2 + x[/tex]
Now we know that Distance traveled by brand A scooter is equal to Brand A scooter top speed multiplied by time reuired to cover the distance by brand A [tex]40.2 = (2+x)3[/tex].
Hence the equation to determine solution is [tex]40.2 = (2+x)3[/tex]
Now we will find the rate of brand B by solving the same we get.
[tex]40.2 = 6+3x\\3x = 40.2-6\\3x = 34.2\\x= 11.4 \ m/h[/tex]
Hence Brand B will travel at a rate of 11.4 miles per hour.
