Answer:
for C-Cl bond [tex]\lambda_1=3.66\times 10^{-9}\ m[/tex]
for O-O bond [tex]\lambda_2=2.43\times 10^{-9}\ m[/tex]
Explanation:
Now as we know the energy of electromagnetic waves is given by:
[tex]E=h.\nu[/tex]
here E = BE
Then for C-Cl:
[tex]327000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_1[/tex]
[tex]\nu_1=8.18733\times 10^{16}\ Hz[/tex]
Now wavelength:
[tex]\lambda_1=\frac{c}{\nu_1}[/tex]
[tex]\lambda_1=\frac{3\times 10^8}{8.18733\times 10^{16}}[/tex]
[tex]\lambda_1=3.66\times 10^{-9}\ m[/tex]
For O2:
[tex]494000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_2[/tex]
[tex]\nu_2=1.236863\times 10^{17}\ Hz[/tex]
Now wavelength:
[tex]\lambda_2=\frac{c}{\nu_2}[/tex]
[tex]\lambda_2=\frac{3\times 10^8}{1.236863\times 10^{17}}[/tex]
[tex]\lambda_2=2.43\times 10^{-9}\ m[/tex]