Answer:
option A
Explanation:
given,
travel distance = 1 mm
diffusion constant for the molecule of oxygen in water = 1 x 10⁻⁹ m²/s
we know that
[tex]t = \dfrac{x^2}{2D}[/tex]
t is the time taken for diffusion
x = 1 mm = 10⁻³ m
D is the diffusion
[tex]t = \dfrac{(10^{-3})^2}{2\times 10^{-9}}[/tex]
[tex]t = \dfrac{(10^{3})}{2}[/tex]
t = 500 s
so, the option to the answer is 170 s
the correct answer is option A
