Respuesta :
Answer:
a) Em = 2.87 10⁻² J , b) A = 0.0152 m , c) v = 0.581 m / s
Explanation:
a) For this problem we will use the energy ratio. Mechanical energy is conserved or we can calculate it in one place. We fear energy for all places. Caicule the mechanical energy in the place where they give data
Em = K + [tex]K_{e}[/tex]
Em = ½ m v² + ½ k x²
Em = ½ 0.170 0.400² + ½ 250 0.0110²
Em = 0.0136 + 0.0151
Em = 0.0287 J
Em = 2.87 10⁻² J
b) to calculate the amplitude we use the energy
Em = ½ k A²
A = √ 2 Em / k
A = √(2 0.0287 / 250)
A = 0.01515 m
A = 0.0152 m
c) the maximum speed
At the point where the elongation is zero, midpoint of the movement, all energy is kinetic and this is the maximum value of the velocity
Em = ½ m v²
v = √2 Em / m
v = √(2 0.0287 / 0.170)
v = 0.581 m / s
